[프로그래머스] SQL고득점킷 _ JOIN

1.

-- 코드를 입력하세요
SELECT ANIMAL_ID, NAME
FROM ANIMAL_OUTS
WHERE ANIMAL_ID 
NOT IN 
(SELECT ANIMAL_INS.ANIMAL_ID
FROM ANIMAL_INS)
ORDER BY ANIMAL_ID;

 

2.

-- 코드를 입력하세요
SELECT I.ANIMAL_ID, I.NAME
FROM ANIMAL_INS I, ANIMAL_OUTS O
WHERE I.ANIMAL_ID = O.ANIMAL_ID AND I.DATETIME > O.DATETIME #시간이 빠르다 - 작은숫자
ORDER BY I.DATETIME ASC; # 시간이 빠른순 - 오름차순

 

3.

-- 코드를 입력하세요
SELECT NAME, DATETIME
FROM ANIMAL_INS
WHERE ANIMAL_ID NOT IN (SELECT ANIMAL_ID
                       FROM ANIMAL_OUTS)
ORDER BY DATETIME ASC
LIMIT 3;

 

4.

-- 코드를 입력하세요
-- SPAYED - O
-- INTACT - X
-- NEUTERED - O
SELECT I.ANIMAL_ID, I.ANIMAL_TYPE, I.NAME
FROM ANIMAL_INS I, ANIMAL_OUTS O
WHERE I.ANIMAL_ID=O.ANIMAL_ID AND 
LEFT(I.SEX_UPON_INTAKE, 1)='I' AND
LEFT(O.SEX_UPON_OUTCOME, 1) !='I'